Let
A_1BC,
AB_1C,
ABC_1 be the equilateral triangles erected outwards the triangle
ABC and
A_2BC,
AB_2C,
ABC_2 the equilateral triangles erected inwards the triangle
ABC. The Fermat points
X_{13} and
X_{14} are the perspectors of
ABC and the triangles
A_1B_1C_1 and
A_2B_2C_2 respetively. We consider the equal distances
d_{13}=AA=BB_1=CC_1 and
d_{14}=AA_2=BB_2=CC_2.
On the other hand, we consider the points
X_{15} and
X_{16}, that are the isogonal conjugates of Fermat points and also are the only points that have equilateral pedal triangles. If we call
l_{15} and
l_{16} the sidelengths of the corresponding pedal triangles, then we have the formula:
d_{13} l_{15} = 2 \Delta = d_{14} l_{16},
where \Delta is the area of the triangle ABC.